prove that 2-√3 is an irrational number?
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Step-by-step explanation:
Let 2 -√3 be a rational number.
⇒ 2 -√3 = p/q; p, q ∈ I, q ≠ 0
⇒√3 = p/q – 2 = (p – 2q)/q
(p – 2q)/q is rational ⇒ √3 is rational number
which is a contradiction
(2 - √3) is an irrational number.
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