Prove that √2+√3 is irrational only one will be given
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Answer:
We assume that 2 + √3 is a rational number. => 2 + √3 = p/q , where p & q are integers, 'q' not = 0. => here, LHS √3 is an irrational number. ... => RHS (p- 2q)/q is a rational number.
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Let √2 + √3 = (a/b) is a rational no
. On squaring both sides ,
we get 2 + 3 + 2√6
= (a2/b2) So,5 + 2√6 = (a2/b2) a rational no.
So, 2√6 = (a2/b2) – 5
Since, 2√6 is an irrational no. and (a2/b2) – 5 is a rational no.
So, my contradiction is wrong. So, (√2 + √3) is an irrational no.
hope it will help you
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