Question

prove that 2^30+2^29+2^28÷2^31+2^30_2^29=7/10
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Answer 1

Answer:

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Answer 2

answer:

=> 2^30+2^29+2^28 / 2^31+ 2^30 - 2^29

=> 2^28(2^2+ 2^1+2^0)/2^28(2^3+2^2-2^1)

=> (4+2+1)/(8+4-2)

=> 7/10

hence, proved