Prove that 2+3root5 is irrational number
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let us assume that 2+3√5 is rational
→ 2+3√5=a/b (where 'a' and 'b' are two co-prims where b ≠0)
→2+3√5=a/b
3√5=a/b -2
3√5= a-2b/b
√5=a-2b/3b
→since, in RHS √5 is equal to LHS but a irrational number cannot be equal to rational number
→this contradiction has arrisen because of our incorrect assumption
→so we conclude that 2+3√5is. irrational number
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