prove that 2+√5 is irrational number
Answers
Step-by-step explanation:
let us assume that 2+√5 is a rational
2+√5= a/b. (a and b are coprimes having common factor 1)
send 2 to rhs
√5=a/b-2
√5= a-2b/b
here a-2b/b is rational
but this contradicts the fact that √5 is irrational
this contradiction has arisen because of our wrong assumption that2+√5 is rational
therefore, 2+√5 is irrational
HENCE PROVED
hope it is useful
Answer:
Let 2+√5 is a rational number so it can be written in p/q form where p and q are integers.
2+√5=p/q
-> √5=p/q-2
-> √5=p-2q/q
since A and b are integers so p-2q/q is rational and so √5 is rational.
but this contradicts the fact that √5 is irrational.
This contradiction has arise and because of our incorrect option that 2+√5 is rational.
Thus we conclude that 2+√5 is an irrational number