prove that √2+ √5 is irrational number
please tell me it's solution step by step
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Use proof by contradiction. Assume that the sum is rationial,
that is
root 2+ root 5 = a/b
where a and b are integers with b≠0. Now rewrite this as
root 5 = a/b - root 2
Squaring both sides of this equation we obtain
5=a square b square −2 root 2 a/b + 2
Now, carefully solve for root 2 and obtain
root 2 = -3b/2a + a/2b
This implies that root 2 is a rational number which is a contradiction. Thus
root 2 + root 5
is an irrational number.
that is
root 2+ root 5 = a/b
where a and b are integers with b≠0. Now rewrite this as
root 5 = a/b - root 2
Squaring both sides of this equation we obtain
5=a square b square −2 root 2 a/b + 2
Now, carefully solve for root 2 and obtain
root 2 = -3b/2a + a/2b
This implies that root 2 is a rational number which is a contradiction. Thus
root 2 + root 5
is an irrational number.
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