Math, asked by snehagupta211005, 25 days ago

prove that√2+√5isanirratonalnumberc​

Answers

Answered by mehakgoel01
1

Step-by-step explanation:

To prove that √2 + √5 is an irrational number, we will use the contradiction method.

Let us assume that √2 + √5 is a rational number with p and q as co-prime integers and q ≠ 0

⇒ √2 + √5 = p/ q

Squaring both sides:

⇒ 7 + 2√10 = p2/q2

⇒ √10 = (p2/q2 - 7) / 2

⇒ We know that (p2/q2 - 7) / 2 is a rational number.

Also, we know √10 = 3.1622776... which is irrational.

Since we know that √10 is an irrational number, but an irrational number can not be equal to a rational number.

This leads to a contradiction that √2 + √5 is a rational number.

Thus, √2 + √5 is an irrational number by contradiction method.

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