prove that 2+5root2 is an irrational number
Answers
Step-by-step explanation:
step 1. let 2+5√2 is rational number than it can be written as a/b where a and b are integer and b is not equal to 0.
step2. 2+5√2 = a/b
5√2 = a/b - 2
5√2 = a -2b/b
√2 = a-2b / 5b
step 3. here we know that a, b,2, and 5 are rational number so the √2 will become rational.
step 4. but this contradicts the fact that √2 is irrational.
so our assumption is wrong that is why 2+5√2 is irrational
Answer:
Step-by-step explanation:
Let us assume to a contarary that 2+5root 2 is a rational number
so, 2+5root2 = a/b
where a and b are co prime numbers and b is not equal to 0
2+5root=a/b
5root2=a/2b
root 2=a/10b
here a,10 and b are integers so
a/10b is a rational number
hence root 2 is also rational
which brings us to a contarary that root 2 is irrational
therefore 2+5root2 is irrational number
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