Prove that
2.7 3.5 5
n n
is divisible by 24 for all
n N .
Answers
Answer:
Let P(n):2.7
n
+3.5
n
−5 is divisible by 24
We note that P(n) is true when n=1, since 2.7+3.5−5=24. which is divisible by 24.
Assume that P(k) is true.
i.e. 2.7
k
+3.5
k
−5=24q when q∈N -------------- ( 1 )
Now, we have to prove that P(k+1) is true whenever P(k) is true.
We have
2.7
k+1
+3.5
k+1
−5
⇒ 2.7
k
.7
1
+3.5
k
.5
1
−5
⇒ 7[2.7
k
+3.5
k
−5−3.5
k
+5]+3.5
k
.5−5
⇒ 7[24q−3.5
k
+5]+15.5
k
−5
⇒ 2×24q−21.5
k
+35+15.5
k
−5
⇒ 7×24q−6.5
k
+30
⇒ 7×24q−6(5
k
−5)
⇒ 7×24q−6(4p) [ (5
k
−5) is multiple of 4 ]
⇒ 7×24q−24p
⇒ 24(7p−q)
⇒ 24×r;r=7p−q. is some natural number ---------- ( 2 )
The expression on the R.H.S oof ( 1 ) is divisible by 24. Thus P(k+1) is true whenever P(k) is true.
Hence, by principle of mathematical induction , P(n) is true for all n∈N.
Step-by-step explanation:
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Answer:
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