prove that (2-7√3) is an irrational number where √3 is irrational.
please help me with this question
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Answer:
Hi let's assume that 2√3-7 is rational
Let,
2√3-7=r, where r is rational
2√3= r+7
√3=r + 7/2
Here,
RHS is purely rational,whereas, LHS is irrational
This is a contradiction.
Hence,
our assumption was wrong.
Therefore,
2√3-7 is an irrational number.
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