Question

prove that √2+√7 is an irrational no.​

Answer 1

Step-by-step explanation:

Answer:

root 2+ root 7

root 2+root 7=a (where a is an integer)

squaring both sides

(root 2+root 7)^2=(a)^2

(root 2)^2+(root 7)^+2(root 2)(root 7)=a^2

2+7+2 root 14=a^2

9+2 root 14 =a^2

2 root 14=a^2-9

root 14=a^2-9/2

since a is an integer therefore a^2-9/2 is also an integer and therefore root 14 is also an integer but integers are not rational numbers therefore root 2+root 7 is an irrational number.

proved.