prove that 2-8√3 is an irrational number
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Answer:
yes ,it is an irrational no.
Step-by-step explanation:
let 2-8√3 is rational no.
2-8√3=p/q( where p and q are coprimes and q is not equal to 0)
-8√3=p/q-2
-8√3=p-2q/q
√3=p-2q/-8
√3=-(-p+2q/8)
here rhs is rational no
therefore √3 is rational no
but this contradict the fact that √3 is irrational no
and this contradiction is arisen due to our wrong assumption that 2-8√3 is rational no
therefore 2-8√3 is an irrational no
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