prove that 2(cos^3x-cosxsin^2x)=cos3x+cosx
Answers
Answered by
0
Answer:
ans
Step-by-step explanation:
LHS :
cos2xcos
2
x
−cos3xcos
2
9x
=
2
1
[2cos2xcos
2
x
−2cos3xcos
2
9x
]
=
2
1
[cos[(2x+
2
x
)+cos(2x−
2
x
)]−[cos(3x+
2
9x
)+cos(
2
9x
−3x)]]
=
2
1
[cos
2
5x
+cos
2
3x
−cos
2
15x
−cos
2
3x
]
=
2
1
[cos
2
5x
−cos
2
15x
]
=
2
1
[2sin5xsin
2
5x
]
=sin5xsin
2
5x
Answered by
23
Answer:
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