Prove that
2 (Cos⁴ 60°+sin⁴30°)-(tan²60° + cot²45°)+3sec²30°= 1/4
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Answer:
L.H.S:
[2(cos⁴ 60°+sin⁴30°)]-(tan²60° + cot²45°)+3sec²30°
=[2{(1/2)^4+(1/2)^4}]-{(√3)^2+(1)^2}+3(2/√3)^2
=2(1/16+1/16)-(3+1)+3×4/3
=(2×1/8)-4+4
=1/4=R.H.S
Hence, proved.
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