prove that 2 divided by under root 7 is irrational
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Let 2/√7 is a rational no.
2/√7=2/√7×(√7/√7)=2√7/7.......(by rationalising)
Now, 2√7/7=p/q.....(as rational no.it can be written as p/q )
2√7=7p/q
√7=7p/2q
see here LHS is irrational where as RHS is rational .
Therefore...it is a wrong Q
so , 2/√7 is an irrational number.
Hope this helps you ....✌✌
THANKS☺☺
2/√7=2/√7×(√7/√7)=2√7/7.......(by rationalising)
Now, 2√7/7=p/q.....(as rational no.it can be written as p/q )
2√7=7p/q
√7=7p/2q
see here LHS is irrational where as RHS is rational .
Therefore...it is a wrong Q
so , 2/√7 is an irrational number.
Hope this helps you ....✌✌
THANKS☺☺
LÈGENDAJ:
you really helped a lot .....was stuck in this question for a while
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