Question

Prove that 2 into sin power 6 theta + cos power 6 theta minus 3 into sin power 4 theta + cos power 4 theta + 1 is equals to zero

Answer 1

Answer:

0

Step-by-step explanation:

$2sin^6\theta + cos^6\theta - 3sin^4\theta +cos^4\theta +1$

So, we have to prove $2sin^6\theta + cos^6\theta - 3sin^4\theta +cos^4\theta +1 = 0$

L.H.S

$2sin^6\theta + cos^6\theta - 3sin^4\theta +cos^4\theta +1$

Let the value $\theta = 90^0$

So,

=$2sin^690^o + cos^6 90^o - 3sin^490^o +cos^490^o +1$

We know that the value of $sin90^o = 1$ and $cos90^o = 0$

Put the values of $sin90^o$  and  $cos90^0$

we get,

$=2 \times 1 + 0 - 3\times 1 + 0 + 1 \\= 2 - 3 + 1\\= 3 - 3\\= 0$

= R.H.S.

Hence Proved