Prove that √2 is an irrational number.
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Answer:
√2=p/q. Squaring both sides,
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.2q²=p² From this equation, we know p² must be even (since it is 2 multiplied by some number). ...
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.2q²=p² From this equation, we know p² must be even (since it is 2 multiplied by some number). ... 2q²=p²=(2m)²=4m² or. ...
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.2q²=p² From this equation, we know p² must be even (since it is 2 multiplied by some number). ... 2q²=p²=(2m)²=4m² or. ... q²=2m² ...
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.2q²=p² From this equation, we know p² must be even (since it is 2 multiplied by some number). ... 2q²=p²=(2m)²=4m² or. ... q²=2m² ... √2=p/q=2m/2n. ...
√2=p/q. Squaring both sides,2=p²/q² The equation can be rewritten as.2q²=p² From this equation, we know p² must be even (since it is 2 multiplied by some number). ... 2q²=p²=(2m)²=4m² or. ... q²=2m² ... √2=p/q=2m/2n. ... √2=m/n.i hope it will help you