Question

prove that √2 is an irrational number ??? ​

Answer 1

Answer:

To prove that √2 is an irrational number, we will use the contradiction method. ⇒ p2 is an even number that divides q2. Therefore, p is an even number that divides q. ... This leads to the contradiction that root 2 is a rational number in the form of p/q with p and q both co-prime numbers and q ≠0

Step-by-step explanation:

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Answer 2

Answer:

Problem statement: Prove that Root 2 is Irrational Number

Given: The number 2

• There are two methods to prove that √2 is an irrational number, and those methods are:

• By contradiction method
• By long-division method

Step-by-step explanation:

• The square root of a number is the number that gets multiplied to itself to give the original number. The square root of 2 is represented as √2. The actual value of √2 is undetermined. The decimal expansion of √2 is infinite because it is non-terminating and non-repeating. Any number that has a non-terminating and non-repeating decimal expansion is always an irrational number. So, √2 is an irrational number.