Question

prove that √2 is an irrational number...
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I will mark the best solution as brainlisttt❣❣
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Answer 1

Step-by-step explanation:

here is your answer....

Answer 2

Let us assume that√2 is rational

Then we find co prime by p/q

√2 = p/q

p=√2q

Squaring both side

(p)² = (√2q)²

p² = 2q²

q² = p²/2

If p² is divisible by 2 so that p is also divided by 2

p²= 2r

q²= (2r)²/2

q² = 4r²/2

q²= 2r²

r² = q²/2

If q² is divisible by 2 so that q is also divided by 2

So p and q both divided by 2

This condition has arisen because our wrong consumption that √5 is rational

So, we conclude that √ 5 is irrational