Question

prove that √2 is irrational​

Answer 1

Step-by-step explanation:

Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction.

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A proof that the square root of 2 is irrational.

2 = (2k)2/b2

b2 = k^2

Answer 2

$\huge \underline \frak \pink {★彡A᭄ɴsᴡᴇʀ彡★}$

Let's suppose √2 is a rational number. Then we can write it √2 = a/b where a, b are whole numbers, b not zero. We additionally assume that this a/b is simplified to lowest terms, since that can obviously be done with any fraction.

A proof that the square root of 2 is irrational.

2 = (2k)²/b²

b² = 2k²

$\large\colorbox{orange}{May Be Helpful ✌️ Dear ✌️}$