Question

Prove that √2 is irritional no

Answer 1

Answer:

Let's consider √2 as rational

and √2 = a/b where a & b are co-primes (which have no factors other than 1)

√2b=a

2b^2 = a^2

b divides a^2 and a divides a

let a = 2c

so 2b^2 = 4c^2

b^2 = 2c^2

now 2 divides b^2 and b

therefore 2 is the common factor for both a & b

but a & b are coprimes

So our assumption is wrong

Therefore √2 is irrational

Hope it's helpful............

Answer 2

Answer:

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