prove that 2(lb+bh+hl )
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Answered by
37
total surface area of all the faces of a cuboidal box = h x l +b x l + b x h + l x h +b x h + l x b = 2 (h x l +b x h+ b x l) = 2 (lb + bh+ hl)
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Answered by
27
if we observe a cuboid
we will see that
top and bottom =lb+lb=2lb
front and back=bh+bh=2bh
left and right=lh+lh=2lh
so,
2lb+2bh+2lh=2(lb+bh+lh)
we will see that
top and bottom =lb+lb=2lb
front and back=bh+bh=2bh
left and right=lh+lh=2lh
so,
2lb+2bh+2lh=2(lb+bh+lh)
rajasvi:
good
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