Question

prove that 2^m and 5^n are terminating decimal​

Answer 1

• In a fraction, if the denominator is of the form 2n∗5 m
• then the fraction is always terminating.
• In this case, 34.12345=3412345/100000
• Denominator is 100000=10/ 5
• =2 /5 ∗5/ 5

• Denominator is of the form 2 n ∗5 m

• So, it is terminating and reason is the correct explanation to assertion

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Answer 2

Answer:

terminating

Step-by-step explanation:

when 2^n×5^m then the expression is always terminating

For example:

34.12345=3412345/100000

Denominator is 100000=105=25∗55

Denominator is of the form 2n∗5m