Math, asked by Mega1906U, 1 year ago

prove that 2^n+6×9^n is always divisible by 7 for any positive integer n​

Answers

Answered by ishucutee
5

Hello!!!!!

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Solution____❤️

 {2}^{n}  + 6 \times  {9}^{n}  \\ n = 1 \\  \\ 2 + 54 = 56 \: divisible \: by \: 7 \\  \\ n = 2 \\ \\ 4 + 486 = 490 \: divisible \: by \: 7 \:

Hence, for all positive values of n the given statement is true.

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Answered by Anonymous
4

HEY MATE HERE IS YOUR ANSWER--

➾2n+6×9n

n=1

➾2+54=56 divisibleby7

➾ n=2

➾ 4+486=490 divisibleby7

Hence, for all positive values of n the given statement is true.!

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