prove that 2 root 3 - 4 is an irrational number
Answers
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Step-by-step explanation:
Given :-
2√3-4
To find :-
Prove that 2√3-4 is an irrational number?
Solution :-
Let us assume that 2√3-4 is a rational number
=> It must be in the form of p/q ,where p and q are integers and q≠0
Let 2√3-4 = a/b ( a,b are co -primes)
=> 2√3 = (a/b)+4
=> 2√3 = (a+4b)/b
=> √3 = (a+4b)/2b
=> √3 is in the form of p/q
=> √3 is a rational number.
But √3 is not a rational number.
√3 is an irrational number.
This contradicts to our assumption that is 2√3-4 is a rational number.
So, 2√3-4 is an irrational number.
Hence , Proved.
Answer:-
2√3-4 is an irrational number.
Used Method:-
- Method of Contradiction or Indirect method
Points to know :-
- The numbers are in the form of p/q,where p and q are integers and q≠0 called rational numbers and they are denoted by Q.
- The numbers are not in the form of p/q,where p and q are integers and q≠0 called irrational numbers and they are denoted by Q' or S.
- If q is a rational number and s is an irrational number then
- q+s is an irrational number.
- q-s is an irrational number.
- q×s is an irrational number.
- q/s is an irrational number.