Question

prove that:
2 sin ^2 A + 3cos A = 0​

Answer 1

2sin²A+3cosA=0

2(1-cos²A)+3cosA=0

2-2cos²A+3cosA=0

2cos²A-3cosA-2=0

cosa={-(-3)±√(-3)²-4.2.(-2)}/2.2

={3±√(9+16)}/4

=(3±5)/4

let +ve sign

cosA=8/4=2, A=cos^-1(2)

let -ve sign

cosA=-2/4=-1/2

cosA=cos120°

A=120°,

Answer 2

Answer:

⭐《ANSWER》

$\huge\mathfrak\pink {ANSWER}$

Step-by-step explanation:

HELLO , I M ANSWERING HERE OF YOUR LATEST QUESTION OF COS^2 (A-B)