Question

Prove that 2 ( sin6 degree theta + cos 6 degree theta) - 3( s in4 degree theta + cos 4 degree) +1 is equal to 0

Answer 1

theta = @ for now...

2 ( sin square @ + cos square @ ) cube - 3 ( sin square @ + cos square @ ) square + 1

= 2 (1) - 3 (1) +1

= 2 - 3 + 1

= 3 - 3

= 0