Prove that 2a2 +2b2 +2c2 -2ab-2bc-2ca = (a-b)2 +(b-c)2 +(c-a)2
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(a-b)2 = a2-2ab+b2 .................. (1)
(b-c)2 = b2-2bc+c2 .................. (2)
(c-a)2 = c2-2ca+a2 ..................(3)
therefor,
2a2+2b2+2c2-2ab-2bc-2ca
=(a2-2ab+b2)+(b2-2bc+c2)+(c2-2ca+a2)
=(a-b)2+(b-c)2+(c-a)2 (from 1,2and 3)
(proved)
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