Prove that 2cos(45+a).cos(45-a)=1-2sin2a
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Answer:
Step-by-step explanation:
45+A) = α
(45-A) = β
2 cos α cos β = cos ( α + β ) + cos ( α - β )
= cos (45+A+45-A) + cos (45+A-(45-A)
= cos (45+A+45-A) + cos (45+A-45+A)
= cos 90 + cos 2A
= 0 + cos 2A
= cos 2A
cos 2A = 1 - 2 sin^2 A
hence proved
hope it helps...regrads
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