Prove that 2m+4n is a factor of 8m³+64n³
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0
Answer:
We need to find common factors of 4m
2
,6m
2
,8m
3
The factor of 4m
2
=2×2×m×m,
6m
2
=3×2×m×m
and that of 8m
3
=2×2×2×m×m×m
Therefore, the common factors are 2×m×m=2m
2
.
Answered by
0
Answer:
there at the cubes so the 2m+4m at the factors sry by mark me as brainliest and thank get it
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