Math, asked by rubyminveni143, 3 months ago

Prove that 2n

+ 6 x 9n

is always divisible by 7 for any positive integer n.​

Answers

Answered by ANAS659
2

Answer:

2n + 6n × 9n

according to BODMAS

2n + 54n

56n

and 56 is divisible by 7

so 56n is divisible by 7

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