prove that (2n) ! / n ! = [ 1.3.5..... ( 2n-1) ] 2^n
using L.H.S
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we can write 2n=1.2.3.4......(2n-1)(2n)
according to question 1.2.3.4.......(2n-1)(2n) /1.2.3......n
2.4......(2n) [1.3.5.....(2n-1)/1.2.3....n
2^n(1.2.3.....n) (1.3.5.....2n-1)/1.2.3.....n
2^n(1.3.5......2n-1)
it is right answer I hope answer is helpful to you &pls mark me as brain list
according to question 1.2.3.4.......(2n-1)(2n) /1.2.3......n
2.4......(2n) [1.3.5.....(2n-1)/1.2.3....n
2^n(1.2.3.....n) (1.3.5.....2n-1)/1.2.3.....n
2^n(1.3.5......2n-1)
it is right answer I hope answer is helpful to you &pls mark me as brain list
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