Question

prove that 2root3-7 is an irrational number​

Answer 1

Answer:

Hi !!

Lets assume that 2√3-7 is rational

Let ,

2√3-7 = r , where r is rational

2√3 = r + 7

√3 = r + 7/2

Here ,

RHS is purely rational , whereas , LHS is irrational

This is a contradiction.

Hence ,

our assumption was wrong.

Therefore ,

2√3-7 is an irrational number

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