Question

Prove that 2rut3 t5rut2 is an irrational number​

Answer 1

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{(a + b)}^{2}(a+b)2 = {a}^{2}a2 + {b}^{2}b2 + 2ab

{(a - b)}^{2}(a−b)2 = {a}^{2}a2 + {b}^{2}b2 - 2ab

{(a)}^{2}(a)2 - {(b)}^{2}(b)2 = (a + b)(a - b)

(x + a)(x - b) = {x}^{2}x2 + (a+b)x + ab

{(a+b+c)}^{2}(a+b+c)2 = {a}^{2}a2 + {b}^{2}b2 + {c}^{2}c2 + 2ab + 2bc + 2ac

Answer 2

Answer:

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{(a + b)}^{2}(a+b)2 = {a}^{2}a2 + {b}^{2}b2 + 2ab

{(a - b)}^{2}(a−b)2 = {a}^{2}a2 + {b}^{2}b2 - 2ab

{(a)}^{2}(a)2 - {(b)}^{2}(b)2 = (a + b)(a - b)

(x + a)(x - b) = {x}^{2}x2 + (a+b)x + ab

{(a+b+c)}^{2}(a+b+c)2 = {a}^{2}a2 + {b}^{2}b2 + {c}^{2}c2 + 2ab + 2bc + 2ac

Step-by-step explanation:

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