prove that 2tan30° \ 1+tan^2 30° =sin 60°
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Firstly taking the LHS:2 tan 30/1 +tan^2 30
Next putting the value of tan 30 i.e √3
2√3/ 1+ (√3)^2
2√3/1+ 3. { Since, [√3]^2 =3}
2√3 /4
√3/2. (SINCE √3/2 = sin 60)
Sin60
Since LHS=RHS,
HENCE PROVED
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