prove that (3, 0) (6, 4) (-1, 3) are vertices of isoselous triangle
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Let A(3, 0), B (6, 4) and C(-1, 3) be the given points
(AFTER THE IMAGE)
⇒ AC=√ (16+9)
⇒ AC=√(25)
⇒ AB2=(√25)2
⇒ AB2=25
⇒ AC2=25
⇒ BC2=(√50)2
⇒ BC2=50
Since AB2+AC2=BC2 and AB=AC
∴ ABC is a right angled isosceles triangle
Hope it helps :)
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