Prove that : (3^1/2)×(3^1/4)×(3^1/8)×………..=3
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Answer:
3^(1/2 + 1/4 + 1/8 + ... ) = 3^1 = 3
Step-by-step explanation:
3^1/2 * 3^1/4 * 3^1/8 ... = 3
3^(1/2 + 1/4 + 1/8 + ... ) = 3
Now we look at 1/2 + 1/4 + 1/8 + ...
1/2 + 1/4 + 1/8 + 1/16 + · · · is an elementary example of a geometric series
The sum of this series can be denoted in summation notation as: 1/2 + 1/4 + 1/8 + 1/16 + · · · = (1/2) / ( 1 - 1/2 ) = 1
-From here it is obvious that 3^(1/2 + 1/4 + 1/8 + ... ) = 3^1 = 3
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