Prove that (√3+1) (√3-1)=2 using this find 2/√3+√1
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To prove ,
(√3+1)(√3-1)=2
To find,
2/(√3+1)
Proof:
Let √3 be equal to a and let 1 be equal to be.
Simplyfying LHS
Substituting the assumed values :-
(a+b)(a-b)
We know, this is in the form of identity :-
(x+y)(x-y) = x^2 - y^2
Putting the values,
a^2 - b^2
Putting values of a and b:
(√3)^2-(1)^2
3-1
2
Hence, proved.
So,
2/(√3+1)
[2×(√3-1)][(√3+1)(√3-1)]
(2√3-2)/2
√3-1 ( Answer )
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