Question

prove that (√3+1) (3- cot 30) = tan^3 60 - 2 sin 60

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Answer 1

Answer:

LHS = (√3+1)(3−cot30)

=3√3−√3cot30+3−3cot30

=3√3−√3cot30+√3√3−√3√3cot30

=3√3−√3cot30(1+√3)+3

=3√3−cot30/tan30(1+√3)+3

=3√3−cot30/tan30 tan45 - cos30/tan30tan30 +cot² 30

=tan³60−2sin60

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