Prove that -3×(1/4)^3 =a+ib
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Step-by-step explanation:
- -3×(1/4) ^3=a+ib
- i^2×3×(1/64) =a+ib
- (i×√3)^2×1/8^2=a+ib
- √3i×1/8=a+ib
.a=1/8 b=√3
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