Prove that √3,2-3√5 square is irrational
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Answer: suppose √3 is a rational
Step-by-step explanation:
√3 = p/q , q≠0 , p & q are having common factor
p & q re integers
squaring on both sides, we get
(√3)²= (p/q)²
⇒ 3 =p²/q²
⇒3q²=p²
⇒q²= p²/3 (1)
⇒p² is divisible by 3
⇒then p is also divisible by 3 (2)
take p= 3r
substitute in (1), we get
⇒q²= (3r)²/3
⇒q²= 9r²/3
⇒q²= 3r²
⇒q²/3= r²
⇒q² is divisible by 3
⇒then q is also divisible by 3 (3)
from (2) and (3), we get
⇒p and q are having a common factor as 3
⇒This is a contradiction hence our supposition is false
∴ √3 is an irrational
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