Prove that 3 + 2√3 is an irrational number.
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Let 3+2√3 is a rational number.
A rational number can be written in the form of p/q.
p,q are integers then (p-6q)/2q is a rational number. ...
Therefore,3+2√3 is an irrational number.
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Let us assume, to the contrary, that 3 + 2√3 is a rational number.
That is, we can find coprime a and b (b not equal to 0) where a and b are integers.
Therefore, 3 + 2√3 = a/b
Rearranging the equation, we get 2√3 = a-3b/b
I.e √3 = a-3b/2b
Since a and b are integers, therefore a-3b/2b is a rational and therefore √3 is rational.
But this contradicts the fact that √3 is irrational.
This contradiction has arisen due to our incorrect assumption that 3 + 2√3 is rational.
Therefore, 3 + 2√3 is an irrational number.
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