prove that 3√2/4 is an irrational no
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Answered by
1
Let 3√2/4 be rational no.
3√2/4=p/q
√2=4p/3q
Here √2 is irrational no.
Therefore rational no.= Irrational no.
This is not possible
Our assumptions b wrong.
Hence 3√2/4 is irrational no.
3√2/4=p/q
√2=4p/3q
Here √2 is irrational no.
Therefore rational no.= Irrational no.
This is not possible
Our assumptions b wrong.
Hence 3√2/4 is irrational no.
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Answered by
0
Heya !!!
Here is your answer :-
Let's assume that 3√2/4 is a rational number.
So, 3√2/4 = p/q , q≠0, p,q both integers.
=> 3√2 = 4p/q
=> √2 = 4p/3q
= integer/ integer
= a rational number
Which contradicts the fact that √2 is irrational.
So, 3√2 /4 is an irrational number.
I hope this helps you dear friend.
Here is your answer :-
Let's assume that 3√2/4 is a rational number.
So, 3√2/4 = p/q , q≠0, p,q both integers.
=> 3√2 = 4p/q
=> √2 = 4p/3q
= integer/ integer
= a rational number
Which contradicts the fact that √2 is irrational.
So, 3√2 /4 is an irrational number.
I hope this helps you dear friend.
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