Prove that 3 -2√5 is an irrational number
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Let us assume 3-2√3 is a rational.
3-2√5 = a/b
Where a, b are integers and
b≠0.
=> 2√5 = 3-a/b
=> 2√5 = (3b-a)/b
=> √5 = (3b-a)/2b
Since , a,b are integers,
(3b-a)/2b is a rational ,So ,
√5 is rational.
But this contradicts the
fact that √5 is irrational.
Therefore,
3-2√5 is an irrational.
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