prove that 3 + 2√5 is irrational
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Answer:
Step-by-step explanation:
Let us assume 3+25√ + is rational.
So we can write this number as
3+25√=ab ---- (1)
Here a and b are two co-prime number and b is not equal to zero.
Simplify the equation (1) subtract 3 both sides, we get
25√=ab−3
25√=a−3bb
Now divide by 2 we get
5√=a−3b2b
Here a and b are integer so a−3b2b is a rational number, so 5√ should be a rational number.
But 5√ is a irrational number, so it is contradict.
Therefore, 3+25√ is irrational number.
Answered by
1
Answer:
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your answer is here !
Step-by-step explanation:
3 + 2√5 = a/ b
2√5 =a/b -3
√5 =a-3b/2b
√5 is rational.
This contradicta the fact that √5 is irrational.
So our supposition is incorrect.
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