Question

Prove that 3 + 2√5 is irrational.​

Answer 1

Let 3 + 2√5 be a rational number.

Then the co-primes x and y of the given rational number where (y ≠ 0) is such that:

3 + 2√5 = x/y

Rearranging, we get,

2√5 = (x/y) – 3

√5 = 1/2[(x/y) – 3]

Since x and y are integers, thus, 1/2[(x/y) – 3] is a rational number.

Therefore, √5 is also a rational number. But this confronts the fact that √5 is irrational.

Thus, our assumption that 3 + 2√5 is a rational number is wrong.

Hence, 3 + 2√5 is irrational.

Answer 2

$\sqrt{5} \: is \: a \: irratioal \: number \: thats \: y \: 3 + 2\sqrt{5} \: is \: too \: irrational \: number$