prove that 3√2/5 is irrational
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Answered by
39
let it 3 root 2 /5 be a rational no.
then 3 root 2/5=p/Q
3 root 2=5p/Q
root 2=5p/3q
LHS is an irrational no.
LHS NOT=RHS
this contradiction is due to our wrong assumption that 3 root 2/5is a rational no.
therefore 3 root 2/5is an irrational no.
then 3 root 2/5=p/Q
3 root 2=5p/Q
root 2=5p/3q
LHS is an irrational no.
LHS NOT=RHS
this contradiction is due to our wrong assumption that 3 root 2/5is a rational no.
therefore 3 root 2/5is an irrational no.
Answered by
23
Answer:
Assume that 3 + √2/5 is a rational no.
= 3 + √2/5 =a/b
= 3 +√2 = 5a/b
√2 = 5a/3b
Since 5,a and 3,b are integers,5a/3b is rational ,so √2 is rational.
But this contradicts the fact that √2 is irrational.
so, we conclude that 3 +√2/5 is irrational no.
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