prove that (3,2),(6,3),(7,6) and(4,5) are the varities of a parallelogram.
Answers
Answered by
4
HELLO........FRIEND!!
THE ANSWER IS HERE,
Let A (3,2) , B (6,3) , C (7,6) , D (4,5) are the vertices of a quadrilateral.
If these points are the vertices of a parallelogram. Then the mid-point of the diagnol AC & BD are equal.
=> [(x1+x3)/2, (y1+y3)/2] = [(x2+x4)/2, (y2+y4)/2]
=> [(3+7)/2, (2+6)/2]=[(6+4)/2, (3+5)/2]
=> [10/2,8/2]=[10/2,8/2]
=> [5,4]=[5,4]
The mid-points of the diagnols are equal .
So, the quadrilateral is a parallelogram.
:-)Hope it helps u.
THE ANSWER IS HERE,
Let A (3,2) , B (6,3) , C (7,6) , D (4,5) are the vertices of a quadrilateral.
If these points are the vertices of a parallelogram. Then the mid-point of the diagnol AC & BD are equal.
=> [(x1+x3)/2, (y1+y3)/2] = [(x2+x4)/2, (y2+y4)/2]
=> [(3+7)/2, (2+6)/2]=[(6+4)/2, (3+5)/2]
=> [10/2,8/2]=[10/2,8/2]
=> [5,4]=[5,4]
The mid-points of the diagnols are equal .
So, the quadrilateral is a parallelogram.
:-)Hope it helps u.
tejasri2:
for square, rectangle also diagonals mid point equal
If diagnol mid-points are equal.Then it may be square or rectangle.But it must be a parellelogram
Square or rectangle also my become naa
Answered by
0
Answer:
It is given that , a= {1,5}, b={3,7} : r=(a,b) and a-b is multiple of 4.
We have to find relation r.
Solution : Consider the following pairs
(1,3)=1 -3= -2,
(1,7) = 1- 7 = -6
(5,3) = 5 -3 =2
(5,7) = 5 - 7 = -2
As , none of the pair (1,3),(1,7), (5,3),)(5,7) satisfies the condition that a-b is multiple of 4, where a= first element of ordered pair and b= Second element of ordered pair.
So→ [r(a, b) such that a-b is multiple of 4], does not form any kind of relation from a to b.
Step-by-step explanation:
Similar questions