Question

prove that 3√2+7 is a irrational ​

Answer 1

Answer:

Explanation:

First , assume that 3root2+7 is rational no.

then, it can be written in the form of a/b where a and b are co-prime no.

3root2+7=a/b

3root2 =a/b-7

root2 =a-7÷3b

root2.= integer-7÷3integer

root2 = rational no.

but this contradicts the fact that root2 is irrational no.

This contradiction has arisen because

of our wrong assumption that 3root2+7 is rational

therefore, 3root2+7 is irrational no.

Hope it helps.