prove that √3+√2 is an irrational number?
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sqrt3 +sqrt2 is irrational number
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I hope this answer may help you
Step-by-step explanation:
Assume √3+√2 as rational
p,q are coprimes
(√3+√2)2 =(p/q)2
(√3)2+(√2)2+2×√3×√2=p2/q2
3+2+2√6=p2/q2
5+2√6=p2/q2
2√6=p2/q2-5
2√6=p2-5q2/q2
√6=p2-5q2/2q2
since p, q are integers RHS is rational
But we know that √6 is irrational
This contradiction has occur because our assumption is wrong
Hence √3+√2 is irrational
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